Jump to content

Leșu

Coordinates: 47°19′N 24°45′E / 47.317°N 24.750°E / 47.317; 24.750
From Wikipedia, the free encyclopedia

This is an old revision of this page, as edited by InternetArchiveBot (talk | contribs) at 10:04, 22 December 2017 (Rescuing 1 sources and tagging 0 as dead. #IABot (v1.6.1)). The present address (URL) is a permanent link to this revision, which may differ significantly from the current revision.

For other uses, see Leșu (disambiguation).
Leșu
Commune
Leșu is located in Romania
Leșu
Leșu
Coordinates: 47°19′N 24°45′E / 47.317°N 24.750°E / 47.317; 24.750
Country Romania
CountyBistrița-Năsăud County
Area
90.10 km2 (34.79 sq mi)
Population
 (2002)[1]
2,995
Time zoneUTC+2 (EET)
 • Summer (DST)UTC+3 (EEST)

Leșu (Hungarian: Les) is a commune in Bistrița-Năsăud County, Romania. It is composed of two villages, Leșu and Lunca Leșului.

47°19′N 24°45′E / 47.317°N 24.750°E / 47.317; 24.750

References

  1. ^ Romanian census data, 2002 Archived 2012-05-17 at the Wayback Machine; retrieved on March 1, 2010
Stub icon

This Bistrița-Năsăud County location article is a stub. You can help Wikipedia by expanding it.

Retrieved from "https://en.wikipedia.org/w/index.php?title=Leșu&oldid=816591972"