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Lovett Island

Coordinates: 35°48′20″N 87°37′04″W / 35.8056218°N 87.6177966°W / 35.8056218; -87.6177966
From Wikipedia, the free encyclopedia

Lovett Island is an island in Hickman County, Tennessee[1] on the Duck River. The island takes it shape from the formation of an oxbow lake.

Lovett Island was named for Jesse Lovett, a pioneer settler.[2]

References

[edit]
  1. ^ U.S. Geological Survey Geographic Names Information System: Lovett Island
  2. ^ Spence, W. Jerome D.; Spence, David L. (1900). A History of Hickman County, Tennessee. Southern Historical Press. p. 272. ISBN 978-0-89308-242-0.

35°48′20″N 87°37′04″W / 35.8056218°N 87.6177966°W / 35.8056218; -87.6177966