1967 Mauritian general election

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General elections were held in Mauritius on 7 August 1967. The result was a victory for the Independence Party, a coalition led by the Labour Party, which won a total of 43 seats,[1] allowing Labour leader and incumbent Prime Minister Seewoosagur Ramgoolam to form a government.

The voting system created twenty constituencies on Mauritius, which each elected three members. Two seats were elected by residents of Rodrigues, and eight seats were filled by a system known as "best losers" whereby the electoral commission would appoint eight unsuccessful candidates to ensure that ethnic minorities were fairly represented.[2] Voter turnout was 88.9%.[3]

Results

Party Votes % Seats +/-
Constituency Best-loser Total
Independence Party[a] 444,737 54.66 39 4 43 +13
Mauritian Social Democrat Party 354,193 43.53 23 4 27 +19
All Mauritian Hindu Congress 7,056 0.87 0 0 0 0
National Socialist Workers Party 1,238 0.15 0 0 0 0
Mauritius Liberation Front 843 0.10 0 0 0 0
Mauritius Workers Party 501 0.06 0 0 0 0
Mauritius Young Communist League 452 0.06 0 0 0 0
Rodrigues Party 232 0.03 0 0 0 0
Total 813,677 100 62 8 70 +30
Source: Electoral Commission, Nohlen et al.

a The Independence Party bloc consisted of the Labour Party (26 seats), the Independent Forward Bloc (12 seats) and the Muslim Committee of Action (5 seats).

References

  1. ^ Nohlen, D, Krennerich, M & Thibaut, B (1999) Elections in Africa: A data handbook, p618 ISBN 0-19-829645-2
  2. ^ Mauritius: Background to the 1967 Legislative Assembly election EISA
  3. ^ Mauritius: 1967 Legislative Assembly election results overview EISA