Tomotilus
Appearance
(Redirected from Oxyptilus celebratus)
Tomotilus | |
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Scientific classification ![]() | |
Domain: | Eukaryota |
Kingdom: | Animalia |
Phylum: | Arthropoda |
Class: | Insecta |
Order: | Lepidoptera |
Family: | Pterophoridae |
Genus: | Tomotilus Yano, 1961 |
Species: | T. celebratus
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Binomial name | |
Tomotilus celebratus (Meyrick, 1932)
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Synonyms | |
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Tomotilus celebratus is a moth of the family Pterophoridae. It has been reported from Australia, India, Japan (including Honshu) and Indonesia (Java).[1] Until recently the species was known as Tomotilus saitoi, but the earlier name Oxyptilus celebratus has been recognised as an earlier reference to this same species.[2]
The length of the forewings is 6–8 mm.
The larvae feed on Dunbaria villosa.
References
[edit]- ^ Beccaloni, G.; Scoble, M.; Kitching, I.; Simonsen, T.; Robinson, G.; Pitkin, B.; Hine, A.; Lyal, C., eds. (2003). "Oxyptilus celebratus". The Global Lepidoptera Names Index. Natural History Museum.
- ^ Kim, Sora; Park, Kyu-Tek; Byun, Bong-Kyu; Lee, Seunghwan (2012). "Taxonomic review of the tribe Oxyptilini (Lepidoptera: Pterophoridae) from Korea". Journal of Asia-Pacific Entomology. 15: 35–43. doi:10.1016/j.aspen.2011.08.006.
External links
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Wikispecies has information related to Tomotilus.
- Taxonomic And Biological Studies Of Pterophoridae Of Japan (Lepidoptera)
- A Check-List Of Microlepidoptera Of India (Part-I: Family Pterophoridae)
- Japanese Moths