Sémelay

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Sémelay
The church in Sémelay
The church in Sémelay
Sémelay is located in France
Sémelay
Sémelay
Coordinates: 46°51′09″N 3°51′07″E / 46.85250°N 3.8519°E / 46.85250; 3.8519Coordinates: 46°51′09″N 3°51′07″E / 46.85250°N 3.8519°E / 46.85250; 3.8519
Country France
Region Bourgogne-Franche-Comté
Department Nièvre
Arrondissement Château-Chinon
Canton Luzy
Government
 • Mayor (2001–2008) Guy Laffaye
Area1 33.53 km2 (12.95 sq mi)
Population (1999)2 279
 • Density 8.3/km2 (22/sq mi)
Time zone CET (UTC+1)
 • Summer (DST) CEST (UTC+2)
INSEE/Postal code 58276 / 58360
Elevation 227–530 m (745–1,739 ft)

1 French Land Register data, which excludes lakes, ponds, glaciers > 1 km² (0.386 sq mi or 247 acres) and river estuaries.

2 Population without double counting: residents of multiple communes (e.g., students and military personnel) only counted once.

Sémelay is a commune in the Nièvre department in central France. The town of Sémelay belongs to the canton of Luzy and the district of Château-Chinon(Ville).[1]

Geography[edit]

The river Alène flows westward through the southern part of commune.

The town's surface is 33.4 km². It is situated at an altitude of about 292 meters. It Is situated "at altitude of about 292 year meters.[2]

Demographics[edit]

At the 1999 census, the population was 279. On 1 January 2004, the estimate was 268.

See also[edit]

References[edit]

  1. ^ "information"
  2. ^ "information"