1912 South Australian state election
Appearance
(Redirected from South Australian state election, 1912)
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All 40 seats in the South Australian House of Assembly 21 seats were needed for a majority | ||||||||||||||||||||||||||||||||||
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State elections were held in South Australia on 10 February 1912. All 40 seats in the South Australian House of Assembly were up for election. The incumbent United Labor Party government led by Premier of South Australia John Verran was defeated by the opposition Liberal Union led by Leader of the Opposition Archibald Peake. Each of the 13 districts elected multiple members, with voters casting multiple votes.
Party | Votes | % | Swing | Seats | Change | |
Liberal Union | 278,277 | 51.41 | +1.83 | 24 | +4 | |
United Labor Party | 253,163 | 46.77 | -2.32 | 16 | -6 | |
Independent | 9,817 | 1.81 | +0.49 | 0 | 0 | |
Total | 541,257 | 40 | -2 | |||
Liberal Union | Win | 24 | +4 | |||
United Labor Party | 16 | -6 |
See also
[edit]- Members of the South Australian House of Assembly, 1912-1915
- Members of the South Australian Legislative Council, 1912–1915
References
[edit]- History of South Australian elections 1857-2006, volume 1: ECSA
- State and federal election results in Australia since 1890