1832 United States presidential election in Alabama
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Elections in Alabama |
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Government |
The 1832 United States presidential election in Alabama took place between November 2 and December 5, 1832, as part of the 1832 United States presidential election. Voters chose seven representatives, or electors to the Electoral College, who voted for President and Vice President.
Alabama voted for the Democratic candidate, Andrew Jackson, over the National Republican candidate, Henry Clay. Jackson won Alabama by a margin of 99.94%.
Results
United States presidential election in Alabama, 1832[1] | |||||
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Party | Candidate | Votes | Percentage | Electoral votes | |
Democratic | Andrew Jackson | 14,286 | 99.97% | 7 | |
National Republican | Henry Clay | 5 | 0.03% | 0 | |
Totals | 14,291 | 100.0% | 7 |
References
- ^ "1832 Presidential General Election Results - Alabama". U.S. Election Atlas. Retrieved 10 April 2013.