1872 United States presidential election in Delaware
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| Elections in Delaware |
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The 1872 United States presidential election in Delaware took place on November 5, 1872, as part of the 1872 United States presidential election. Voters chose three representatives, or electors to the Electoral College, who voted for president and vice president.
Delaware voted for the Republican candidate, Ulysses S. Grant, over Liberal Republican candidate Horace Greeley. Grant won Delaware by a margin of 4.24%.
Results
| United States presidential election in Delaware, 1872[1][2] | ||||||||
|---|---|---|---|---|---|---|---|---|
| Party | Candidate | Running mate | Popular vote | Electoral vote | ||||
| Count | % | Count | % | |||||
| Republican | Ulysses S. Grant of Ohio | Henry Wilson of Massachusetts | 11,129 | 51.00% | 3 | 100.00% | ||
| Liberal Republican | Horace Greely of New York | Benjamin Gratz Brown of Missouri | 10,205 | 46.76% | 0 | 0.00% | ||
| Straight-Out Democratic | Charles O'Conor | John Quincy Adams II | 488 | 2.24% | 0 | 0.00% | ||
| Total | 21,822 | 100.00% | 3 | 100.00% | ||||
References
- ^ "1872 Presidential General Election Results - Delaware". U.S. Election Atlas. Retrieved 6 March 2018.
- ^ "1872 Presidential Election". The American Presidency Project. University of California Santa Barbara. Retrieved 3 December 2017.
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