1828 United States presidential election in Maine
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Elections in Maine |
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The 1828 United States presidential election in Maine took place between October 31 and December 2, 1828, as part of the 1828 United States presidential election. Voters chose nine representatives, or electors to the Electoral College, who voted for President and Vice President.
Maine voted for the National Republican candidate, John Quincy Adams, over the Democratic candidate, Andrew Jackson. Adams won Maine by a margin of 19.68%.
Results
United States presidential election in Maine, 1828[1] | |||||
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Party | Candidate | Votes | Percentage | Electoral votes | |
National Republican | John Quincy Adams | 20,773 | 59.71% | 8 | |
Democratic | Andrew Jackson | 13,927 | 40.03% | 1 | |
N/A | Other | 89 | 0.26% | 0 | |
Totals | 34,700 | 100.0% | 9 |
References
- ^ "1828 Presidential General Election Results - Maine". U.S. Election Atlas. Retrieved 28 February 2013.