1848 United States presidential election in Rhode Island
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| Elections in Rhode Island |
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The 1848 United States presidential election in Rhode Island took place between November 7, 1844, as part of the 1848 United States presidential election. Voters chose four representatives, or electors to the Electoral College, who voted for President and Vice President.
Rhode Island voted for the Whig candidate, Zachary Taylor, over Democratic candidate Lewis Cass and Free Soil candidate former president Martin Van Buren. Taylor won the state by a margin of 28.09%.
Results
| United States presidential election in Rhode Island, 1848[1] | ||||||||
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| Party | Candidate | Running mate | Popular vote | Electoral vote | ||||
| Count | % | Count | % | |||||
| Whig | Zachary Taylor of Louisiana | Millard Fillmore of New York | 6,779 | 60.77% | 4 | 100.00% | ||
| Democratic | Lewis Cass of Michigan | William O. Butler of Kentucky | 3,646 | 32.68% | 0 | 0.00% | ||
| Free Soil | Martin Van Buren of New York | Charles Francis Adams, Sr. of Massachusetts | 730 | 6.54% | 0 | 0.00% | ||
| Total | 11,155 | 100.00% | 4 | 100.00% | ||||
References
State and district results of the 1848 United States presidential election | ||
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