1860 United States presidential election in Wisconsin
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Elections in Wisconsin |
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The 1860 United States presidential election in Wisconsin was held on November 6, 1860. Wisconsin voters chose five electors to the Electoral College, who voted for president and vice president.
Republican Party candidate Abraham Lincoln won the state with 57% of the popular vote, winning Wisconsin's five electoral votes.
Results
United States presidential election in Wisconsin, 1860[1] | ||||||||
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Party | Candidate | Running mate | Popular vote | Electoral vote | ||||
Count | % | Count | % | |||||
Republican | Abraham Lincoln of Illinois | Hannibal Hamlin of Maine | 86,113 | 56.59% | 5 | 100.00% | ||
Democratic | Stephen A. Douglas of Illinois | Herschel Vespasian Johnson of Georgia | 65,021 | 42.73% | 0 | 0.00% | ||
Southern Democratic | John C. Breckinridge of Kentucky | Joseph Lane of Oregon | 888 | 0.58% | 0 | 0.00% | ||
Constitutional Union | John Bell of Tennessee | Edward Everett of Massachusetts | 161 | 0.11% | 0 | 0.00% | ||
Total | 152,183 | 100.00% | 5 | 100.00% |