1992 United States presidential election in the District of Columbia

Main article: United States presidential election, 1992

United States presidential election in the District of Columbia, 1992

November 3, 1992

Nominee Bill Clinton George H.W. Bush Party Democratic Republican Home state Arkansas Texas Running mate Al Gore Dan Quayle Electoral vote 3 0 Popular vote 192,619 20,698 Percentage 84.64% 9.10%

President before election George H. W. Bush Republican Elected President Bill Clinton Democratic

The 1992 United States presidential election in the District of Columbia took place on November 3, 1992, as part of the 1992 United States presidential election. Voters chose three representatives, or electors to the Electoral College, who voted for President and Vice President.

The District of Columbia, heavily Democratic, was won in a landslide by Governor Bill Clinton (D-Arkansas) with 84.64% of the popular vote over incumbent President George H.W. Bush (R-Texas) with 9.10%. Businessman Ross Perot (I-Texas) finished in third with 4.25% of the popular vote. Clinton ultimately won the national vote, defeating incumbent President Bush and Perot.

Results

United States presidential election in the District of Columbia, 1992
Party		Candidate	Votes	Percentage	Electoral votes
	Democratic	Bill Clinton	192,619	84.64%	3
	Republican	George H.W. Bush (incumbent)	20,698	9.10%	0
	Independent	Ross Perot	9,681	4.26%	0
	New Alliance	Lenora Fulani	1,459	0.64%	0
	Independent	Ronald Daniels	1,446	0.64%	0
	Libertarian	Andre Marrou	467	0.21%	0
	N/A	Write-ins	1,202	0.53%	0
Totals			227,572	100.0%	3