Talk:1971 Tour de France

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Total distance/average speed[edit]

There seems to be uncertainty about the total distance (and hence average velocity - the winning time is consistent in different sources):

The box on this page quotes:

  • Distance (d): 4118 km (suspiciously close to the 4117 km of 1969)
  • Winning time (t): 96h 45' 14" (= 96.754 h)
  • Average velocity (v): 38.084 km/h
  • hence, d/t = 42.562 km/h - internally inconsistent and a bit high

The body text quotes:

  • d = 3689 km
  • v = 36.925 km/h
  • hence, using d/v = 99.905 h; probably too high (t may well be the most trustworthy value)

The sum of the stage lengths on this page gives:

  • d = 3584.2 km
  • so that, using the winning time of 96.754 h, v = 37.044 km/h — Preceding unsigned comment added by AstroFloyd (talkcontribs) 09:12, 23 July 2013 (UTC)

LeTour.fr gives:

  • d = 3608 km
  • v = 38.084 km/h
  • t = 96h 45' 14"
  • hence, d/t = 37.290 km/h; internally inconsistent

AstroFloyd (talk) 18:43, 22 July 2013 (UTC)