1880 United States presidential election in Vermont
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| Elections in Vermont |
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The 1880 United States presidential election in Vermont took place on November 2, 1880, as part of the 1880 United States presidential election. Voters chose 5 representatives, or electors to the Electoral College, who voted for President and Vice President.
Vermont voted for the Republican nominee, James A. Garfield, over the Democratic nominee, Winfield Scott Hancock. Garfield won Vermont by a margin of 41.66%.
Results
| United States presidential election in Vermont, 1880[1] | ||||||||
|---|---|---|---|---|---|---|---|---|
| Party | Candidate | Running mate | Popular vote | Electoral vote | ||||
| Count | % | Count | % | |||||
| Republican | James Abram Garfield of Ohio | Chester Alan Arthur of New York | 45,091 | 69.81% | 5 | 100.00% | ||
| Democratic | Winfield Scott Hancock of Pennsylvania | William Hayden English of Indiana | 18,182 | 28.15% | 0 | 0.00% | ||
| Greenback | James Baird Weaver of Iowa | Barzillai Jefferson Chambers of Texas | 1,212 | 1.88% | 0 | 0.00% | ||
| N/A | Others | Others | 109 | 0.17% | 0 | 0.00% | ||
| Total | 48,829 | 100.00% | 5 | 100.00% | ||||
References
- ^ {{cite web|title=1880 Presidential General Election Results - Vermont|url=http://uselectionatlas.org/RESULTS/state.php?fips=50&year=1880&f=1&off=0
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