1998 Dutch Open – Doubles

From Wikipedia, the free encyclopedia

This is an old revision of this page, as edited by Jevansen (talk | contribs) at 05:36, 26 February 2016 (disambiguate link). The present address (URL) is a permanent link to this revision, which may differ significantly from the current revision.

Doubles
1998 Dutch Open
Final
ChampionsAustralia Jacco Eltingh
Netherlands Paul Haarhuis[1]
Runners-upSlovakia Dominik Hrbatý
Slovakia Karol Kučera
Score6–3, 6–2
Events
Singles men women
Doubles men women
← 1997 · Dutch Open · 1999 →

The 1998 Dutch Open was an ATP-tournament held in Amsterdam, Netherlands. The tournament was held from August 3 to August 9.

Seeds

Champion seeds are indicated in bold text while text in italics indicates the round in which those seeds were eliminated.

2

Draw

Key

Finals

First Round Quarterfinals Semifinals Final[1]
1 Netherlands J Eltingh
Netherlands P Haarhuis
4 6 6
South Africa C Haggard
United States J Waite
6 3 3 1 Netherlands J Eltingh
Netherlands P Haarhuis
6 3 6
Netherlands J van Lottum
Netherlands D van Scheppingen
7 6 6 Netherlands J van Lottum
Netherlands D van Scheppingen
3 6 3
Czech Republic L Pimek
Czech Republic T Anzari
6 7 4 1 Netherlands J Eltingh
Netherlands P Haarhuis
6 3 6
Sweden F Bergh
Czech Republic P Vízner
6 6 6 Sweden F Bergh
Czech Republic P Vízner
3 6 3
3 Netherlands T Kempers
Argentina D Orsanic
4 7 3 Sweden F Bergh
Czech Republic P Vízner
6 3 6
Argentina M Hood
Belgium T Vanhoudt
7 6 Argentina M Hood
Belgium T Vanhoudt
1 6 2
Netherlands S Noteboom
Argentina M Puerta
6 1 1 Netherlands J Eltingh
Netherlands P Haarhuis
6 6
Czech Republic C Doseděl
Russia A Olhovskiy
4 7 6 Slovakia D Hrbatý
Slovakia K Kučera
3 2
South Africa M Barnard
South Africa B Barnard
6 6 1 Czech Republic C Doseděl
Russia A Olhovskiy
w/o
Hungary G Köves
South Africa P Rosner
6 4 7 Hungary G Köves
South Africa P Rosner
4 Czech Republic J Novák
Czech Republic D Rikl
2 6 6 Czech Republic C Doseděl
Russia A Olhovskiy
6 3 4
Socialist Federal Republic of Yugoslavia N Djordjevic
Australia J Holmes
7 6 6 Slovakia D Hrbatý
Slovakia K Kučera
2 6 6
Argentina P Albano
Brazil F Meligeni
6 7 1 Socialist Federal Republic of Yugoslavia N Djordjevic
Australia J Holmes
5 7 2
Slovakia D Hrbatý
Slovakia K Kučera
5 6 6 Slovakia D Hrbatý
Slovakia K Kučera
7 6 6
2 United Kingdom N Broad
South Africa P Norval
7 4 3

References

  1. ^ a b "1998 Amsterdam". International Tennis Federation. Retrieved 1 January 2015.