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2005 Tennis Masters Cup – Doubles

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Doubles
2005 Tennis Masters Cup
Final
ChampionsFrance Michaël Llodra
France Fabrice Santoro
Runners-upIndia Leander Paes
Serbia and Montenegro Nenad Zimonjić
Score6–7(6–8), 6–3, 7–6(7–4)
Events
Singles Doubles
← 2004 · Tennis Masters Cup · 2006 →

Bob Bryan and Mike Bryan were the defending champions, but lost in the semifinals to Michaël Llodra and Fabrice Santoro.

Michaël Llodra and Fabrice Santoro won in the final 6–7(6–8), 6–3, 7–6(7–4), against Leander Paes and Nenad Zimonjić.

Seeds

  1. United States Bob Bryan / United States Mike Bryan (Semifinals)
  2. Sweden Jonas Björkman / Belarus Max Mirnyi (Round Robin)
  3. Zimbabwe Wayne Black / Zimbabwe Kevin Ullyett (Semifinals)
  4. The Bahamas Mark Knowles / Canada Daniel Nestor (Round Robin)
  5. India Leander Paes / Serbia and Montenegro Nenad Zimonjić (Final)
  6. France Michaël Llodra / France Fabrice Santoro (Champions)
  7. Australia Wayne Arthurs / Australia Paul Hanley (Round Robin)
  8. Australia Stephen Huss / South Africa Wesley Moodie (Round Robin)

Draw

Key

Finals

Semifinals Final
          
1 United States Bob Bryan
United States Mike Bryan
3 67  
6 France Michaël Llodra
France Fabrice Santoro
6 79  
6 France Michaël Llodra
France Fabrice Santoro
66 6 77
5 India Leander Paes
Serbia and Montenegro Nenad Zimonjić
78 3 64
3 Zimbabwe Wayne Black
Zimbabwe Kevin Ullyett
3 4  
5 India Leander Paes
Serbia and Montenegro Nenad Zimonjić
6 6  

Red Group

  United States Bryan
United States Bryan
The Bahamas Knowles
Canada Nestor
India Paes
Serbia and Montenegro Zimonjić
Australia Arthurs
Australia Hanley
RR
W–L
Set
W–L
Game
W–L
Standings
1 United States Bob Bryan
United States Mike Bryan
6–4, 6–4 7–5, 6–7(5–7), 7–6(9–7) 5–7, 7–6(7–3), 6–7(4–7) 2–1 5–3
(62.50%)
50–46 1
4 The Bahamas Mark Knowles
Canada Daniel Nestor
4–6, 4–6 5–7, 7–5, 3–6 3–6, 4–6 0–3 1–6 30–42 4
5 India Leander Paes
Serbia and Montenegro Nenad Zimonjić
5–7, 7–6(7–5), 6–7(7–9) 7–5, 5–7, 6–3 7–6(7–3), 7–6(8–6) 2–1 5–3
(62.50%)
50–47 2
7 Australia Wayne Arthurs
Australia Paul Hanley
7–5, 6–7(3–7), 7–6(7–4) 6–3, 6–4 6–7(3–7), 6–7(6–8) 2–1 4–3
(57.14%)
44–39 3

Standings are determined by: 1) Number of wins; 2) Number of matches; 3) In two-players-ties, head-to-head records; 4) In three-players-ties, percentage of sets won, or of games won; 5) Steering Committee decision.

Gold Group

  Sweden Björkman
Belarus Mirnyi
Zimbabwe Black
Zimbabwe Ullyett
France Llodra
France Santoro
Australia Huss
South Africa Moodie
RR
W–L
Set
W–L
Game
W–L
Standings
2 Sweden Jonas Björkman
Belarus Max Mirnyi
5–7, 6–4, 4–6 6–7(3–7), 4–6 2–6, 4–6 0–3 1–6 31–42 4
3 Zimbabwe Wayne Black
Zimbabwe Kevin Ullyett
7–5, 4–6, 6–4 3–6, 6–3, 6–4 3–6, 7–6(7–1), 6–2 3–0 6–3 48–42 1
6 France Michaël Llodra
France Fabrice Santoro
7–6(7–3), 6–4 6–3, 3–6, 4–6 6–4, 4–1r 2–1 5–2 36–30 2
8 Australia Stephen Huss
South Africa Wesley Moodie
6–2, 6–4 6–3, 6–7(1–7), 2–6 4–6, 1–4r 1–2 3–4 31–32 3

Standings are determined by: 1) Number of wins; 2) Number of matches; 3) In two-players-ties, head-to-head records; 4) In three-players-ties, percentage of sets won, or of games won; 5) Steering Committee decision.