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2018 ATP Finals – Doubles

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Doubles
2018 ATP Finals
2017 ChampionsFinland Henri Kontinen
Australia John Peers
Events
Singles Doubles
← 2017 · ATP Finals · 2019 →

Henri Kontinen and John Peers were the two-time defending champions, but they only qualified for the first alternate spot.[1] Kontinen and Peers replaced Nikola Mektić and Alexander Peya for the last match in the round robin competition.

Seeds

Alternates

  1. Finland Henri Kontinen / Australia John Peers (Replaced Mektić/Peya, Round robin)
  2. Netherlands Jean-Julien Rojer / Romania Horia Tecău (Did not play)

Draw

Key

Finals

Semifinals Final
          
8 France Pierre-Hugues Herbert
France Nicolas Mahut
2 Colombia Juan Sebastián Cabal
Colombia Robert Farah
 
5 United States Mike Bryan
United States Jack Sock
4 United Kingdom Jamie Murray
Brazil Bruno Soares
3 6 [4]
5 United States Mike Bryan
United States Jack Sock
6 4 [10]

Group Knowles/Nestor

Austria Marach
Croatia Pavić
Poland Kubot
Brazil Melo
United States Bryan
United States Sock
France Herbert
France Mahut
RR W–L Set W–L Game W–L Standings
1 Austria Oliver Marach
Croatia Mate Pavić
6–7(4–7), 4–6 4–6, 6–7(4–7) 6–4, 7–6(7–3) 1–2 2–4 33–36 4
3 Poland Łukasz Kubot
Brazil Marcelo Melo
7–6(7–4), 6–4 3–6, 6–7(5–7) 2–6, 4–6 1–2 2–4 28–35 3
5 United States Mike Bryan
United States Jack Sock
6–4, 7–6(7–4) 6–3, 7–6(7–5) 2–6, 2–6 2–1 4–2 30–31 2
8 France Pierre-Hugues Herbert
France Nicolas Mahut
4–6, 6–7(3–7) 6–2, 6–4 6–2, 6–2 2–1 4–2 34–23 1

Group Llodra/Santoro

Colombia Cabal
Colombia Farah
United Kingdom Murray
Brazil Soares
South Africa Klaasen
New Zealand Venus
Croatia Mektić
Austria Peya
Finland Kontinen
Australia Peers
RR W–L Set W–L Game W–L Standings
2 Colombia Juan Sebastián Cabal
Colombia Robert Farah
4–6, 3–6 6–3, 7–6(7–5) 6–3, 6–4
(w/ Mektić/Peya)
2–1 4–2 32–28 2
4 United Kingdom Jamie Murray
Brazil Bruno Soares
6–4, 6–3 7–6(7–5), 4–6, [10–5] 3–6, 7–6(7–3), [10–3]
(w/ Kontinen/Peers)
3–0 6–2 35–31 1
6 South Africa Raven Klaasen
New Zealand Michael Venus
3–6, 6–7(5–7) 6–7(5–7), 6–4, [5–10] 7–6(7–5), 7–6(7–5)
(w/ Mektić/Peya)
1–2 3–4 35–37 3
7

9
Croatia Nikola Mektić
Austria Alexander Peya
Finland Henri Kontinen
Australia John Peers
3–6, 4–6
(w/ Mektić/Peya)
6–3, 6–7(3–7), [3–10]
(w/ Kontinen/Peers)
6–7(5–7), 6–7(5–7)
(w/ Mektić/Peya)
0–2

0–1
0–4

1–2
19–26

12–11
X

4

Standings are determined by: 1. Number of wins; 2. Number of matches; 3. In two-player ties, head-to-head records; 4. In three-player ties, percentage of sets won, then percentage of games won, then ATP rankings[2]

References

  1. ^ "Draw Announced For 2018 Nitto ATP Finals". ATP. 5 November 2018.
  2. ^ "Semi-final Qualifying Procedure". Nitto ATP Finals. Retrieved 14 November 2018.