2019 Ilkley Trophy – Women's doubles

Women's doubles
2019 Ilkley Trophy
Champions	Beatriz Haddad Maia Luisa Stefani
Runners-up	Ellen Perez Arina Rodionova
Score	6–4, 6–7(5–7), [10–4]

Main article: 2019 Ilkley Trophy

Asia Muhammad and Maria Sanchez were the defending champions, but lost in the semifinals to Ellen Perez and Arina Rodionova.

Beatriz Haddad Maia and Luisa Stefani won the title, defeating Perez and Rodionova 6–4, 6–7^(5–7), [10–4], in the final.

Seeds

1. Irina-Camelia Begu / Monica Niculescu (quarterfinals, withdrew)
2. Asia Muhammad / Maria Sanchez (semifinals)
3. Ellen Perez / Arina Rodionova (final)
4. Anna Blinkova / Peng Shuai (semifinals)

Draw

Key

• Q = Qualifier
• WC = Wild card
• LL = Lucky loser
• Alt = Alternate
• SE = Special exempt
• PR = Protected ranking
• ITF = ITF entry
• JE = Junior exempt
• w/o = Walkover
• r = Retired
• d = Defaulted
• SR = Special ranking

Draw

	First round							Quarterfinals							Semifinals							Final
	1	I-C Begu M Niculescu	4	6	[11]
		L Kerkhove W Osuigwe	6	4	[9]			1	I-C Begu M Niculescu
	WC	N Bains M Lumsden	3	6	[7]				B Haddad Maia L Stefani	w/o
		B Haddad Maia L Stefani	6	2	[10]											B Haddad Maia L Stefani	77	6
	4	A Blinkova S Peng	6	6											4	A Blinkova S Peng	64	3
		N Hibino Y Wickmayer	4	2				4	A Blinkova S Peng	w/o
		S Fichman V Savinykh	3	2					Y Duan L Zhu
		Y Duan L Zhu	6	6																			B Haddad Maia L Stefani	6	65	[10]
		X Jiang Q Tang	62	3																		3	E Perez Ar Rodionova	4	77	[4]
		C Lister C Perrin	77	6					C Lister C Perrin	5	0
		C Dolehide E Shibahara	1	3				3	E Perez Ar Rodionova	7	6
	3	E Perez Ar Rodionova	6	6											3	E Perez Ar Rodionova	6	64	[10]
		O Danilović I Jorović	4	6	[4]										2	A Muhammad M Sanchez	2	77	[7]
		M Brengle I Neel	6	4	[10]				M Brengle I Neel	4	64
	WC	O Nicholls K Swan	6	4	[8]			2	A Muhammad M Sanchez	6	77
	2	A Muhammad M Sanchez	2	6	[10]

External links

• Main Draw