1840 United States presidential election in Virginia
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| Elections in Virginia |
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The 1840 United States presidential election in Virginia took place between October 30 and December 2, 1840, as part of the 1840 United States presidential election. Voters chose 23 representatives, or electors to the Electoral College, who voted for President and Vice President.
Virginia voted for the Democratic candidate, incumbent President Martin Van Buren, over Whig candidate William Henry Harrison. Van Buren narrowly won Virginia by a margin of 1.3%, or 1,120 votes.
Results
| United States presidential election in Virginia, 1840[1] | |||||
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| Party | Candidate | Votes | Percentage | Electoral votes | |
| Democratic | Martin Van Buren (inc.) | 43,757 | 50.65% | 23 | |
| Whig | William H. Harrison | 42,637 | 49.35% | 0 | |
| Totals | 86,394 | 100.0% | 23 | ||
References
- ^ "1840 Presidential General Election Results - Virginia". U.S. Election Atlas. Retrieved 12 April 2013.
State and district results of the 1840 United States presidential election | ||
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