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2003 If Stockholm Open – Doubles

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Doubles
2003 If Stockholm Open
Final
ChampionsSweden Jonas Björkman
Australia Todd Woodbridge
Runners-upAustralia Wayne Arthurs
Australia Paul Hanley
Score6–3, 6–4
Events
Singles Doubles
← 2002 · If Stockholm Open · 2004 →

Wayne Black and Kevin Ullyett were the defending champions but lost in the quarterfinals to Wayne Arthurs and Paul Hanley.

Jonas Björkman and Todd Woodbridge won in the final 6–3, 6–4 against Arthurs and Hanley.

Seeds

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Draw

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Key

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First round Quarterfinals Semifinals Final
1 Sweden J Björkman
Australia T Woodbridge
6 6  
  Sweden S Aspelin
Italy M Bertolini
1 1   1 Sweden J Björkman
Australia T Woodbridge
w/o    
  United States R Leach
United States B MacPhie
78 65 77   United States R Leach
United States B MacPhie
     
ALT Australia P Baccanello
Italy D Sanguinetti
68 77 65 1 Sweden J Björkman
Australia T Woodbridge
6 7  
3 United States J Palmer
Czech Republic D Rikl
3 6 6 WC Sweden J Johansson
Sweden A Vinciguerra
3 5  
  South Africa W Ferreira
United States R Ginepri
6 2 1 3 United States J Palmer
Czech Republic D Rikl
64 6 3
  United States M Fish
United States G Oliver
4 6 64 WC Sweden J Johansson
Sweden A Vinciguerra
77 2 6
WC Sweden J Johansson
Sweden A Vinciguerra
6 4 77 1 Sweden J Björkman
Australia T Woodbridge
6 6  
ALT Croatia M Ančić
Slovakia K Beck
77 3 6 2 Australia W Arthurs
Australia P Hanley
3 4  
  Finland J Nieminen
Thailand P Srichaphan
64 6 3 ALT Croatia M Ančić
Slovakia K Beck
     
  South Africa R Koenig
South Africa W Moodie
4 4   4 Argentina G Etlis
Argentina M Rodríguez
w/o    
4 Argentina G Etlis
Argentina M Rodríguez
6 6   4 Argentina G Etlis
Argentina M Rodríguez
65 4  
  Zimbabwe W Black
Zimbabwe K Ullyett
65 6 6 2 Australia W Arthurs
Australia P Hanley
77 6  
WC Sweden J Landsberg
Sweden R Söderling
77 2 4   Zimbabwe W Black
Zimbabwe K Ullyett
2 77 65
  United States D Bowen
Australia A Fisher
3 4   2 Australia W Arthurs
Australia P Hanley
6 62 77
2 Australia W Arthurs
Australia P Hanley
6 6  
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