1884 United States presidential election in Florida
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| Turnout | 22.26% of the total population  3.11 pp[1] | |||||||||||||||||||||||||
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| Elections in Florida |
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 Government |
The 1884 United States presidential election in Florida took place on November 4, 1884, as part of the 1884 United States presidential election. Florida voters chose four representatives, or electors, to the Electoral College, who voted for president and vice president.[2]
Florida was won by Grover Cleveland, the 28th governor of New York, (D–New York), running with the former governor of Indiana Thomas A. Hendricks, with 52.96% of the popular vote, against Secretary of State James G. Blaine (R-Maine), running with Senator John A. Logan, with 46.73% of the vote.[2]
Results
| United States presidential election in Florida, 1884[2] | ||||||||
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| Party | Candidate | Running mate | Popular vote | Electoral vote | ||||
| Count | % | Count | % | |||||
| Democratic | Grover Cleveland of New York | Thomas A. Hendricks of Indiana | 31,769 | 52.96% | 4 | 100.00% | ||
| Republican | James G. Blaine of Maine | John A. Logan of Illinois | 28,031 | 46.73% | 0 | 0.00% | ||
| Write-in | Write-in of | Write-in of | 118 | 0.20% | 0 | 0.00% | ||
| Prohibition | John St. John of Kansas | William Daniel of Maryland | 72 | 0.12% | 0 | 0.00% | ||
| Total | 59,990 | 100.00% | 4 | 100.00% | ||||
References
- ^ "1884 Presidential Election Results Florida Total Population Turnout".
{{cite web}}: Cite has empty unknown parameter:|1=(help) - ^ a b c "1884 Presidential Election Results Florida".
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