1824 United States presidential election in Missouri
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Elections in Missouri |
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This article describes the United States presidential election, 1824, in Missouri.
Missouri has been voting in presidential elections since 1820.
The 1824 United States presidential election was a complex realigning election following the collapse of the prevailing Democratic-Republican Party, resulting in four different candidates each claiming to carry the banner of the party, and competing for influence in different parts of the country. The election was the only one in history to be decided by the House of Representatives under the provisions of the Twelfth Amendment to the United States Constitution after no candidate secured a majority of the electoral vote. It was also the only presidential election in which the candidate who received a plurality of electoral votes (Andrew Jackson) did not become President, a source of great bitterness for Jackson and his supporters, who proclaimed the election of Adams a corrupt bargain.
Voters chose three representatives, or electors to the Electoral College, who voted for President and Vice President. Missouri voted for the Democratic-Republican candidate, Henry Clay.
Results
United States presidential election in Missouri, 1824 | |||||
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Party | Candidate | Votes | Percentage | Electoral votes | |
Democratic-Republican | Henry Clay | 2,042 | 59.50% | 3 | |
Democratic-Republican | Andrew Jackson | 1,166 | 33.97% | 0 | |
Democratic-Republican | William H. Crawford | 32 | 0.93% | 0 | |
N/A | Others | 33 | 0.96% | 0 | |
Totals | 3,273 | 100.0% | 3 |
References
https://uselectionatlas.org/RESULTS/state.php?year=1824&f=1&off=0&elect=0&fips=29&submit=Retrieve