1892 United States presidential election in Missouri

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United States presidential election in Missouri, 1892

← 1888 November 8, 1892 1896 →
  StephenGroverCleveland.png Benjamin Harrison, head and shoulders bw photo, 1896.jpg James B. Weaver 1892.jpg
Nominee Grover Cleveland Benjamin Harrison James B. Weaver
Party Democratic Republican Populist
Home state New York Indiana Iowa
Running mate Adlai Stevenson I Whitelaw Reid James G. Field
Electoral vote 17 0 0
Popular vote 268,400 227,646 41,204
Percentage 49.56% 42.03% 7.61%

President before election

Benjamin Harrison
Republican

Elected President

Grover Cleveland
Democratic

The 1892 United States presidential election in Missouri took place on November 8, 1892. All contemporary 44 states were part of the 1892 United States presidential election. Missouri voters chose seventeen electors to the Electoral College, which selected the president and vice president.

Missouri was won by the Democratic nominees, former President Grover Cleveland of New York and his running mate Adlai Stevenson I of Illinois.

Results[edit]

United States presidential election in Missouri, 1892[1]
Party Candidate Votes Percentage Electoral votes
Democratic Grover Cleveland 268,400 49.56% 17
Republican Benjamin Harrison (incumbent) 227,646 42.03% 0
People's James Weaver 41,204 7.61% 0
Prohibition John Bidwell 4,333 0.80% 0
Totals 541,583 100.00% 17
Voter turnout

References[edit]

  1. ^ Dave Leip’s U.S. Election Atlas; Presidential General Election Results – Missouri

Notes[edit]