1840 United States presidential election in Missouri
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| Elections in Missouri |
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The 1840 United States presidential election in Missouri took place between October 30 and December 2, 1840, as part of the 1840 United States presidential election. Voters chose four representatives, or electors to the Electoral College, who voted for President and Vice President.
Missouri voted for the Democratic candidate, Martin Van Buren, over Whig candidate William Henry Harrison. Van Buren won Missouri by a margin of 13.26%.
Election Results
| United States presidential election in Missouri, 1840[1] | ||||||||
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| Party | Candidate | Running mate | Popular vote | Electoral vote | ||||
| Count | % | Count | % | |||||
| Democratic | Martin Van Buren of New York | Richard M. Johnson of Kentucky | 29,969 | 56.63% | 4 | 100.00% | ||
| Whig | William Henry Harrison of Ohio | John Tyler of Virginia | 22,954 | 43.37% | 0 | 0.00% | ||
| Total | 52,923 | 100.00% | 4 | 100.00% | ||||
References
- ^ "1840 Presidential General Election Results - Missouri". Dave Leip's Atlas of U.S. Presidential Elections. Retrieved 23 December 2013.
State and district results of the 1840 United States presidential election | ||
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