Sherman Township, Antelope County, Nebraska
Sherman Township | |
|---|---|
 Location in Antelope County | |
| Coordinates: 42°23′27″N 098°14′27″W / 42.39083°N 98.24083°W | |
| Country | United States |
| State | Nebraska |
| County | Antelope |
| Area | |
| • Total | 35.81 sq mi (92.75 km2) |
| • Land | 35.77 sq mi (92.65 km2) |
| • Water | 0.04 sq mi (0.10 km2) 0.11% |
| Elevation | 1,755 ft (535 m) |
| Population (2010) | |
| • Total | 103 |
| • Density | 3/sq mi (1.1/km2) |
| GNIS feature ID | 0838246 |
Sherman Township is one of twenty-four townships in Antelope County, Nebraska, United States. The population was 103 at the 2010 census.[1]
See also
References
- ^ "Geographic Identifiers: 2010 Demographic Profile Data (G001): Sherman township, Antelope County, Nebraska". U.S. Census Bureau, American Factfinder. Archived from the original on February 12, 2020. Retrieved June 27, 2013.
External links
Municipalities and communities of Antelope County, Nebraska, United States | ||
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| Cities |  | |
| Villages | ||
| Townships | ||
| Footnotes | ‡This populated place also has portions in an adjacent county or counties | |
 | This Nebraska state location article is a stub. You can help Wikipedia by expanding it. |