1876 United States presidential election in New Jersey
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| Elections in New Jersey |
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The 1876 United States presidential election in New Jersey took place on November 7, 1876, as part of the 1876 United States presidential election. Voters chose 9 representatives, or electors to the Electoral College, who voted for president and vice president.
New Jersey voted for the Democratic nominee, Samuel J. Tilden, over the Republican nominee, Rutherford B. Hayes. Tilden won the state by a narrow margin of 5.65%.
Results
| 1876 United States presidential election in New Jersey[1] | ||||||||
|---|---|---|---|---|---|---|---|---|
| Party | Candidate | Running mate | Popular vote | Electoral vote | ||||
| Count | % | Count | % | |||||
| Democratic | Samuel J. Tilden of New York | Thomas A. Hendricks of Indiana | 115,962 | 52.66% | 9 | 100.00% | ||
| Republican | Rutherford B. Hayes of Ohio | William A. Wheeler of New York | 103,517 | 47.01% | 0 | 0.00% | ||
| Greenback | Peter Cooper of New York | Samuel Fenton Cary of Ohio | 714 | 0.32% | 0 | 0.00% | ||
| Total | 220,193 | 100.00% | 9 | 100.00% | ||||
References
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