Exterior covariant derivative

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In mathematics, the exterior covariant derivative is an analog of an exterior derivative that takes into account the presence of a connection.

Definition[edit]

Let G be a Lie group and PM be a principal G-bundle on a smooth manifold M. Suppose there is a connection on P; this yields a natural direct sum decomposition of each tangent space into the horizontal and vertical subspaces. Let be the projection to the horizontal subspace.

If ϕ is a k-form on P with values in a vector space V, then its exterior covariant derivative is a form defined by

where vi are tangent vectors to P at u.

Suppose that ρ : G → GL(V) is a representation of G on a vector space V. If ϕ is equivariant in the sense that

where , then is a tensorial (k + 1)-form on P of the type ρ: it is equivariant and horizontal (a form ψ is horizontal if ψ(v0, ..., vk) = ψ(hv0, ..., hvk).)

By abuse of notation, the differential of ρ at the identity element may again be denoted by ρ:

Let be the connection one-form and the representation of the connection in That is, is a -valued form, vanishing on the horizontal subspace. If ϕ is a tensorial k-form of type ρ, then

[1]

where, following the notation in Lie algebra-valued differential form § Operations, we wrote

Unlike the usual exterior derivative, which squares to 0, the exterior covariant derivative does not. In general, one has, for a tensorial zero-form ϕ,

[2]

where F = ρ(Ω) is the representation in of the curvature two-form Ω. The form F is sometimes referred to as the field strength tensor, in analogy to the role it plays in electromagnetism. Note that D2 vanishes for a flat connection (i.e. when Ω = 0).

If ρ : G → GL(Rn), then one can write

where is the matrix with 1 at the (i, j)-th entry and zero on the other entries. The matrix whose entries are 2-forms on P is called the curvature matrix.

Exterior covariant derivative for vector bundles[edit]

When ρ : G → GL(V) is a representation, one can form the associated bundle E = Pρ V. Then the exterior covariant derivative D given by a connection on P induces an exterior covariant derivative (sometimes called the exterior connection) on the associated bundle, this time using the nabla symbol:

Here, Γ denotes the sheaf of local sections of the vector bundle. The extension is made through the correspondence between E-valued forms and tensorial forms of type ρ (see tensorial forms on principal bundles.)

Requiring ∇ to satisfy Leibniz's rule, ∇ also acts on any E-valued form; thus, it is given on decomposable elements of the space of -valued k-forms by

.

For a section s of E, we also set

where is the contraction by X.

Conversely, given a vector bundle E, one can take its frame bundle, which is a principal bundle, and so obtain an exterior covariant differentiation on E (depending on a connection). Identifying tensorial forms and E-valued forms, one may show that

which can be easily recognized as the definition of the Riemann curvature tensor on Riemannian manifolds.

Examples[edit]

  • If ω is the connection form on P, then Ω = is called the curvature form of ω.
  • Bianchi's second identity, which says that the exterior covariant derivative of Ω is zero (that is, DΩ = 0) can be stated as: .

Notes[edit]

  1. ^ If k = 0, then, writing for the fundamental vector field (i.e., vertical vector field) generated by X in on P, we have:
    ,
    since ϕ(gu) = ρ(g−1)ϕ(u). On the other hand, (X#) = 0. If X is a horizontal tangent vector, then and . For the general case, let Xi's be tangent vectors to P at some point such that some of Xi's are horizontal and the rest vertical. If Xi is vertical, we think of it as a Lie algebra element and then identify it with the fundamental vector field generated by it. If Xi is horizontal, we replace it with the horizontal lift of the vector field extending the pushforward πXi. This way, we have extended Xi's to vector fields. Note the extension is such that we have: [Xi, Xj] = 0 if Xi is horizontal and Xj is vertical. Finally, by the invariant formula for exterior derivative, we have:
    ,
    which is .
  2. ^ Proof: Since ρ acts on the constant part of ω, it commutes with d and thus
    .
    Then, according to the example at Lie algebra-valued differential form § Operations,
    which is by E. Cartan's structure equation.

References[edit]