Shurab-e Nusazi

From Wikipedia, the free encyclopedia
  (Redirected from Shurab, Gonabad)
Jump to: navigation, search
Shurab-e Nusazi
شوراب نوسازي
village
Shurab-e Nusazi is located in Iran
Shurab-e Nusazi
Shurab-e Nusazi
Coordinates: 34°22′00″N 58°51′06″E / 34.36667°N 58.85167°E / 34.36667; 58.85167Coordinates: 34°22′00″N 58°51′06″E / 34.36667°N 58.85167°E / 34.36667; 58.85167
Country  Iran
Province Razavi Khorasan
County Gonabad
Bakhsh Central
Rural District Pas Kalut
Population (2006)
 • Total 168
Time zone IRST (UTC+3:30)
 • Summer (DST) IRDT (UTC+4:30)

Shurab-e Nusazi (Persian: شوراب نوسازي‎‎, also Romanized as Shūrāb-e Nūsāzī; also known as Shūr Āb)[1] is a village in Pas Kalut Rural District, in the Central District of Gonabad County, Razavi Khorasan Province, Iran. At the 2006 census, its population was 168, in 64 families.[2]

References[edit]

  1. ^ Shurab-e Nusazi can be found at GEOnet Names Server, at this link, by opening the Advanced Search box, entering "-3085336" in the "Unique Feature Id" form, and clicking on "Search Database".
  2. ^ "Census of the Islamic Republic of Iran, 1385 (2006)". Islamic Republic of Iran. Archived from the original (Excel) on 2011-11-11.