Talk:16550 UART

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Not a microprocessor[edit]

A UART is not a microprocessor! This has been in the article for years! --Wtshymanski 15:16, 13 Apr 2005 (UTC)

16550 vs 16550A[edit]

Early 16550 chips had a bug, which allowed them to only really function as 16450 chips, this was fixed with the 16550A and later revisions.

Uploaded an image...[edit]

...and yet I have no ambition to learn the Wiki syntax to link the silly thing into the article. It's up at http://en.wikipedia.org/wiki/Image:Exar16550onItronixPCB.jpg if somebody with a clue wants to handle that. Thanks. Myself248 08:14, 12 October 2007 (UTC)

Dates[edit]

It would be nice to have the dates they were first released listed somewhere. --68.48.43.61 (talk) 2012-03-02 14:36:59 (UTC)

The introduction year for the 16550A is July 1987. The 16550 introduction is unclear. Bytesock (talk) 22:51, 14 April 2016 (UTC)

Baud or BPS?[edit]

I'm wondering about the part that says: "At speeds higher than 9600 baud[...]". Is baud correct here, or should it read BPS? --80.222.99.8 (talk) 12:11, 29 November 2015 (UTC)

BAUD is correct, because that is the speed at the hardware level, and the preferred word to use in UART discussions. As an example, 8N1 (8 bit of data, no party, 1 stop bit) is a total of 10 "bit times" at the hardware level, because there is 1 start bit, 8 data bits, 1 stop bit. For this same example, BPS would be 80% of the BAUD rate, because 8 divided by 10. • SbmeirowTalk • 07:27, 30 November 2015 (UTC)
Baud is the number of symbols per second on the line. So a modem that is capable of giving the user 9600 bit/s will actually only send 2400 symbols per second on the PSTN line which is bandwidth limited to 3000 Hz. This is usually done by amplitude and phase shifting and can be viewed using eye diagrams etc on a oscilloscope. However the 2400 baud/s modem will in this case demand the UART can handle 9600 bits/s. That asynchronous serial throws away 20% is another story. Bytesock (talk) 22:48, 14 April 2016 (UTC)