Talk:Narayana number

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Mathematics rating:
Start Class
Low Importance
 Field: Discrete mathematics

Some trouble with the formula ?[edit]

It seems, according to Sloane, that the formula should read

N(n,k)=\frac1k {n \choose {k-1}}{n-1\choose k-1}

ManiacParisien (talk) 12:40, 4 December 2013 (UTC)