# Talk:Narayana number

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Field: Discrete mathematics

## Some trouble with the formula ?

It seems, according to Sloane, that the formula should read

${\displaystyle N(n,k)={\frac {1}{k}}{n \choose {k-1}}{n-1 \choose k-1}}$

ManiacParisien (talk) 12:40, 4 December 2013 (UTC)