1992 United States presidential election in Idaho
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 County Results
Clinton—>70%
Clinton—60-70%
Clinton—50-60%
Clinton—40-50%
Bush—40-50%
Bush—50-60%
Bush—60-70%
Bush—>70%
Perot—40-50% | |||||||||||||||||||||||||||||||||
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| Elections in Idaho |
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The 1992 United States presidential election in Idaho took place on November 3, 1992, as part of the 1992 United States presidential election. Voters chose four representatives, or electors to the Electoral College, who voted for President and Vice President.
Idaho was won by incumbent President George H.W. Bush (R-Texas) with 42.03% of the popular vote over Governor Bill Clinton (D-Arkansas) with 28.42%. Businessman Ross Perot (I-Texas) finished in a close third with 27.05% of the popular vote.[1] Clinton ultimately won the national vote, defeating both incumbent President Bush and Perot.[2]
Results
| United States presidential election in Idaho, 1992[1] | |||||
|---|---|---|---|---|---|
| Party | Candidate | Votes | Percentage | Electoral votes | |
| Republican | George H.W. Bush (incumbent) | 202,645 | 42.03% | 4 | |
| Democratic | Bill Clinton | 137,013 | 28.42% | 0 | |
| Independent | Ross Perot | 130,395 | 27.05% | 0 | |
| America First | James "Bo" Gritz | 10,281 | 2.13% | 0 | |
| Libertarian | Andre Marrou | 1,167 | 0.24% | 0 | |
| New Alliance Party | Lenora Fulani | 613 | 0.13% | 0 | |
| Totals | 482,114 | 100.0% | 4 | ||
References
- ^ a b "1992 Presidential General Election Results - Idaho". U.S. Election Atlas. Retrieved 8 June 2012.
- ^ "1992 Presidential General Election Results". U.S. Election Atlas. Retrieved 8 June 2012.
