United States presidential election in Missouri, 1840

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United States presidential election in Missouri, 1840
← 1836 October 30 - December 2, 1840 1844 →
  MartinVanBuren.png WHenryHarrison.png
Nominee Martin Van Buren William Henry Harrison
Party Democratic Whig
Home state New York Ohio
Running mate none John Tyler
Electoral vote 4 0
Popular vote 29,969 22,954
Percentage 56.63% 43.37%

President before election

Martin Van Buren

Elected President

William Henry Harrison

The 1840 United States presidential election in Missouri took place between October 30 and December 2, 1840, as part of the 1840 United States presidential election. Voters chose four representatives, or electors to the Electoral College, who voted for President and Vice President.

Missouri voted for the Democratic candidate, Martin Van Buren, over Whig candidate William Henry Harrison. Van Buren won Missouri by a margin of 13.26%.


United States presidential election in Missouri, 1840[1]
Party Candidate Running mate Popular vote Electoral vote
Count % Count %
Democratic Martin Van Buren of New York Richard M. Johnson of Kentucky 29,969 56.63% 4 100.00%
Whig William Henry Harrison of Ohio John Tyler of Virginia 22,954 43.37% 0 0.00%
Total 52,923 100.00% 4 100.00%


  1. ^ "1840 Presidential General Election Results - Missouri". U.S. Election Atlas. Retrieved 23 December 2013.