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1844 United States presidential election in Vermont

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United States presidential election in Vermont, 1844

← 1840 November 1 - December 4, 1840 1848 →
 
Nominee Henry Clay James K. Polk
Party Whig Democratic
Home state Kentucky Tennessee
Running mate Theodore Frelinghuysen George M. Dallas
Electoral vote 6 0
Popular vote 26,780 18,049
Percentage 54.84 36.96

President before election

John Tyler
Independent

Elected President

James K. Polk
Democratic

The 1844 United States presidential election in Vermont took place between November 1 and December 4, 1844, as part of the 1844 United States presidential election. Voters chose six representatives, or electors to the Electoral College, who voted for President and Vice President.

Vermont voted for the Whig candidate, Henry Clay, over Democratic candidate James K. Polk and Liberty candidate James G. Birney. Clay won Vermont by a margin of 17.88%.

Results

United States presidential election in Vermont, 1844[1]
Party Candidate Running mate Popular vote Electoral vote
Count % Count %
Whig Henry Clay of Kentucky Theodore Frelinghuysen of New York 26,780 54.84% 6 100.00%
Democratic James K. Polk of Tennessee George M. Dallas of Pennsylvania 18,049 36.96% 0 0.00%
Liberty Party (1840s) James G. Birney of Michigan Thomas Morris of Ohio 3,970 8.13% 0 0.00%
N/A Others Others 30 0.06% 0 0.00%
Total 48,829 100.00% 6 100.00%

References

  1. ^ "1844 Presidential General Election Results - Vermont". U.S. Election Atlas. Retrieved 23 December 2013.