1992 United States presidential election in Washington (state)

Main article: United States presidential election, 1992

United States presidential election in Washington, 1992

November 3, 1992

Nominee Bill Clinton George H.W. Bush Ross Perot Party Democratic Republican Independent Home state Arkansas Texas Texas Running mate Al Gore Dan Quayle James Stockdale Electoral vote 11 0 0 Popular vote 993,037 731,234 541,780 Percentage 43.4% 32.0% 23.7%

County Results   Clinton—>70%   Clinton—60-70%   Clinton—50-60%   Clinton—40-50%   Bush—40-50%   Bush—50-60%   Bush—60-70%   Bush—>70%   Perot—40-50%

President before election George H. W. Bush Republican Elected President Bill Clinton Democratic

The 1992 United States presidential election in Washington took place on November 3, 1992, as part of the 1992 United States presidential election. Voters chose eleven representatives, or electors to the Electoral College, who voted for President and Vice President.

Washington was won by Governor Bill Clinton (D-Arkansas) with 43.41% of the popular vote over incumbent President George H.W. Bush (R-Texas) with 31.97%. Businessman Ross Perot (I-Texas) finished in third with 23.68% of the popular vote. Clinton ultimately won the national vote, defeating incumbent President Bush.

Results

United States presidential election in Washington, 1992
Party		Candidate	Votes	Percentage	Electoral votes
	Democratic	Bill Clinton	993,037	43.41%	11
	Republican	George H.W. Bush (incumbent)	731,234	31.97%	0
	Independent	Ross Perot	541,780	23.68%	0
	Libertarian	Andre Marrou	7,533	0.33%	0
	America First	James "Bo" Gritz	4,854	0.21%	0
	Natural Law	John Hagelin	2,456	0.11%	0
	U.S. Taxpayers'	Howard Phillips	2,354	0.10%	0
	New Alliance	Lenora Fulani	1,776	0.08%	0
	Independent	Ronald Daniels	1,171	0.05%	0
	Democrats for Economic Recovery	Lyndon LaRouche	855	0.04%	0
	Socialist Workers	James Warren	515	0.02%	0
Totals			2,287,565	100.0%	11