User talk:Leegrc

A belated welcome!

Here's wishing you a belated welcome to Wikipedia, Leegrc. I see that you've already been around a while and wanted to thank you for your contributions. Though you seem to have been successful in finding your way around, you may benefit from following some of the links below, which help editors get the most out of Wikipedia:

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Again, welcome! benmoore 16:38, 22 July 2014 (UTC)[reply]

Edit to Illegal immigration

hi,

I understand you point of view and while it may seem intuitive to some of us, it may not be obvious to some. Generally Wikipedia prefers including published sources that agree with the provided information. This practice of quoting reliable sources holds good for most cases and is especially important in cases such as this where the information might be seen as offensive to some. The reason there is a problems section is again due to the fact that it quotes a source.

In short please find a published source that talks about the benefits of banning some forms of immigration before adding a benefits section. thanks, Pvpoodle (talk) 20:20, 8 October 2014 (UTC)[reply]

Disambiguation link notification for January 13

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Quantile estimation from a sample

I have moved this discussion to the talk page for the Quantile article. Leegrc (talk) 13:44, 21 September 2015 (UTC)[reply]

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BERKOM's contribution to Quantile Talk

I have been preparing my first contribution to Wikipedia. To check how it works, I saved the first chapter and when it seemed to work, deleted it. Somehow it appeared again. Since it is meaningless alone, I hope that neither Wikipedia nor you are active in returning it.

Now I have learnt how to write mathematical expressions in Wikipedia, but there seems to be a misconception in my formulation and fixing it may take time.

Don't worry, I am not one of the former contributors on Quantile Talk page. But to be clear, I try to use their notation and imitate their wording whenever possible. For a non-native English speaker it is also the easiest way. 84.250.125.99 (talk) 06:37, 15 December 2015 (UTC)BERKOM[reply]

Belated reply to email

I have just discovered an email from you, which you sent 8 days ago, but which went into my spam folder, and I didn't see it. I see that the block has been changed to "anon only", so presumably the problem is over, but I will just give an answer to one of the points you mentioned in your email. You said that it seems quite unlikely that the corporation you work for "would choose a web host provider that was any degree of shady". I am sure that is true, but the point is not that the web host provider might be "shady", but that some people using the web host provider might be shady, using a web host provider for dishonest purposes, such as to evade blocks, or to help support a fiction that they are more than one person, so as to give a false impression of independent support from multiple editors in a discussion, or other such deceptive purposes. I have no idea whether that has happened in this case, but it certainly has with some web host providers in the past: it's the motives of some Wikipedia editors who use web host services that may be "shady", not those of the web host providers. Any way, I hope as far as you are concerned the problem is over, and you won't be troubled by blocks again. The editor who uses the pseudonym "JamesBWatson" (talk) 16:04, 19 February 2016 (UTC)[reply]

Ah, you have explained why it started working again. Thank you for that and for the clarification about web host providers. 𝕃eegrc (talk) 16:15, 19 February 2016 (UTC)[reply]

Floor Function

Sir, you still didn't listen. It's not the sign of x. Idk where you got that idea in your head from. It computes whether a number is greater than another and what does efficiency have to do with it? It's a mathematical formula, rather than a computer science operator. I feel like you're trying to mix the two when it reality this function is instead mathematics version.

TheGreatDuckINH (talk) 18:42, 7 March 2016 (UTC)[reply]

I believe that you are saying that we can check

z \geq y

by plugging

z - y

in for

x

in the formula

floor(x / (x^2 + 1)^(1/2)) + 1

. I agree that this is a true statement. Unfortunately, it does not follow that this information belongs in the Wikipedia article. The surest way to win acceptance of the text is to show that a reliable source considers it noteworthy. 𝕃eegrc (talk) 18:49, 7 March 2016 (UTC)[reply]

"...we can check $z \geq y$ by plugging $z - y$ in for $x$ in the formula $floor(x / (x^2 + 1)^(1/2)) + 1$ "

Heh heh heh. That's an incredibly trivial use, but I'll admit it's true as well. No, the thing I'm trying to say is that we can use it in mathematics as an actual formula. For instance:

x*(x>=0)=y

That, is the sort of things it can be used for. Rather than being a checking method of some kind it's an actual operator with a formula tied to it that can be actual used in building equations. You can't do that by just "plugging in numbers". It would defy the very principle that formulas in mathematics should have equations tied to them, not algorithms. Of course, you can still debate notability issues and all that. I'm just saying it's not as stupid as you think.

TheGreatDuckINH (talk) 19:02, 7 March 2016 (UTC)[reply]

People would write it as you just have

x *(x >=0) = y

or using the Heaviside step function

x * θ (x) = y

or via similar compact means. If you are not looking for an algorithm to compute it, why bother writing out

x * (floor(x / (x^2 + 1)^(1/2)) + 1) = y

? 𝕃eegrc (talk) 19:30, 7 March 2016 (UTC)[reply]

Because an expression is not an algorithm.

TheGreatDuckINH (talk) 19:32, 7 March 2016 (UTC)[reply]

incompleteness

I undid your most recent revision as I think it's simply too strong a statement to say 'based on' right in the intro...the article could use some more info about the 'diagonal lemma' and the similarities to Cantor etc but just not right at the top like that...go to that talk page if would like..68.48.241.158 (talk) 15:04, 11 July 2016 (UTC)[reply]

Moving discussion to Talk:Gödel's incompleteness theorems 𝕃eegrc (talk) 15:16, 11 July 2016 (UTC)[reply]

re: Continued fraction article

Merged with discussion on User talk:Mindotaur#Continued fraction article.

In regard to this edit, I've added to the article a terse explanation of why I used "ar-" rather than "arc-". Michael Hardy (talk) 16:42, 7 November 2016 (UTC)[reply]

ArbCom Elections 2016: Voting now open!

Hello, Leegrc. Voting in the 2016 Arbitration Committee elections is open from Monday, 00:00, 21 November through Sunday, 23:59, 4 December to all unblocked users who have registered an account before Wednesday, 00:00, 28 October 2016 and have made at least 150 mainspace edits before Sunday, 00:00, 1 November 2016.

The Arbitration Committee is the panel of editors responsible for conducting the Wikipedia arbitration process. It has the authority to impose binding solutions to disputes between editors, primarily for serious conduct disputes the community has been unable to resolve. This includes the authority to impose site bans, topic bans, editing restrictions, and other measures needed to maintain our editing environment. The arbitration policy describes the Committee's roles and responsibilities in greater detail.

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ArbCom 2017 election voter message

Hello, Leegrc. Voting in the 2017 Arbitration Committee elections is now open until 23.59 on Sunday, 10 December. All users who registered an account before Saturday, 28 October 2017, made at least 150 mainspace edits before Wednesday, 1 November 2017 and are not currently blocked are eligible to vote. Users with alternate accounts may only vote once.

The Arbitration Committee is the panel of editors responsible for conducting the Wikipedia arbitration process. It has the authority to impose binding solutions to disputes between editors, primarily for serious conduct disputes the community has been unable to resolve. This includes the authority to impose site bans, topic bans, editing restrictions, and other measures needed to maintain our editing environment. The arbitration policy describes the Committee's roles and responsibilities in greater detail.

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