Bucov
From Wikipedia, the free encyclopedia
(Redirected from Bucov, Prahova)
For the village in Argeş County, see Râca.
| Bucov | |||
|---|---|---|---|
| — Commune — | |||
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| Coordinates: 44°58′N 26°5′E / 44.967°N 26.083°ECoordinates: 44°58′N 26°5′E / 44.967°N 26.083°E | |||
| Country |  Romania |
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| County | Prahova County | ||
| Status | Commune | ||
| Government | |||
| • Mayor | Ion Savu | ||
| Area | |||
| • Total | 49.03 km2 (18.93 sq mi) | ||
| Population (2002) | |||
| • Total | 10,500 | ||
| Time zone | EET (UTC+2) | ||
| • Summer (DST) | EEST (UTC+3) | ||
Bucov (Romanian pronunciation: [ˈbukov]) is a commune in Prahova County, Romania, just east of Ploieşti, the county seat. It is composed of five villages: Bighilin, Bucov, Chiţorani, Pleaşa and Valea Orlei.
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