1896 United States presidential election in Pennsylvania: Difference between revisions
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| Elections in Pennsylvania |
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 Government |
The 1896 United States presidential election in Pennsylvania took place on November 3, 1896 throughout 45 states. Voters chose 32 representatives, or electors to the Electoral College, who voted for President and Vice President.
Pennsylvania overwhelmingly voted for the Republican nominee, former governor of Ohio William McKinley, over the Democratic nominee, former U.S. Representative from Nebraska William Jennings Bryan. McKinley won Pennsylvania by a landslide margin of 24.71%.
Results
| United States presidential [1] | |||||
|---|---|---|---|---|---|
| Party | Candidate | Votes | Percentage | Electoral votes | |
| Republican | William McKinley | 728,300 | 60.98% | 32 | |
| Democratic | William Jennings Bryan | 433,228 | 36.27% | 0 | |
| Prohibition | Joshua Levering | 19,274 | 1.61% | 0 | |
| National Democratic | John Palmer | 11,000 | 0.92% | 0 | |
| Socialist Labor | Charles Matchett | 1,683 | 0.14% | 0 | |
| National Party | Charles Bentley | 870 | 0.07% | 0 | |