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1998 tennis event results
Brenda Schultz-McCarthy was the defending champion, but decided not to participate this year.
Tara Snyder won her maiden WTA singles title, defeating Chanda Rubin 4–6, 6–4, 7–6(8–6) in the final.
Top half[edit]
Bottom half[edit]
References[edit]
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Grand Slam events | |
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Tier I tournaments | |
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Tier II tournaments |
- Sydney (S, D)
- Paris (S, D)
- Hanover (S, D)
- Linz (S, D)
- Amelia Island (S, D)
- Hamburg (S, D)
- Eastbourne (S, D)
- Stanford (S, D)
- San Diego (S, D)
- Los Angeles (S, D)
- New Haven (S, D)
- Tokyo (S, D)
- Filderstadt (S, D)
- Leipzig (S, D)
- Philadelphia (S, D)
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Tier III tournaments |
- Gold Coast (S, D)
- Oklahoma City (S, D)
- Tokyo Outdoor (S, D)
- Strasbourg (S, D)
- Madrid (S, D)
- Birmingham (S, D)
- Rosmalen (S, D)
- Prague (S, D)
- Warsaw (S, D)
- Boston (S, D)
- Quebec City (S, D)
- Luxembourg (S, D)
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Tier IV tournaments |
- Auckland (S, D)
- Hobart (S, D)
- Bogotá (S, D)
- Makarska (S, D)
- Budapest (S, D)
- Bol (S, D)
- Maria Lankowitz (S, D)
- Palermo (S, D)
- Sopot (S, D)
- Istanbul (S, D)
- Pattaya City (S, D)
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Team events | |
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