Jump to content

1988 Tel Aviv Open – Doubles

From Wikipedia, the free encyclopedia
Doubles
1988 Tel Aviv Open
Final
ChampionsThe Bahamas Roger Smith
Kenya Paul Wekesa
Runners-upWest Germany Patrick Baur
West Germany Alexander Mronz
Score6–3, 6–3
Events
Singles Doubles
← 1987 · Tel Aviv Open · 1989 →

Gilad Bloom and Shahar Perkiss were the defending champions, but lost in the first round this year.

Roger Smith and Paul Wekesa won the title, defeating Patrick Baur and Alexander Mronz 6–3, 6–3 in the final.

Seeds

[edit]

Draw

[edit]

Key

[edit]

Draw

[edit]
First round Quarterfinals Semifinals Final
1 Israel A Mansdorf
South Africa C van Rensburg
6 7  
  Israel G Bloom
Israel S Perkiss
3 6   1 Israel A Mansdorf
South Africa C van Rensburg
6 6 6
  Sweden R Båthman
New Zealand D Lewis
6 6     Sweden R Båthman
New Zealand D Lewis
3 7 2
  Israel S Glickstein
Israel O Weinberg
3 4   1 Israel A Mansdorf
South Africa C van Rensburg
6 6 4
3 Brazil D Marcelino
Brazil M Menezes
4 6     The Bahamas R Smith
Kenya P Wekesa
3 7 6
  Sweden C Allgårdh
Sweden D Engel
6 7     Sweden C Allgårdh
Sweden D Engel
2 3  
  The Bahamas R Smith
Kenya P Wekesa
7 4 6   The Bahamas R Smith
Kenya P Wekesa
6 6  
  Israel A Naor
Israel Menashe Tzur
5 6 3   The Bahamas R Smith
Kenya P Wekesa
6 6  
  Brazil J Soares
West Germany M Westphal
6 6   4 West Germany P Baur
West Germany A Mronz
3 3  
  United States L Jensen
West Germany D Keretić
1 3     Brazil J Soares
West Germany M Westphal
7 6 5
  Austria A Antonitsch
Belgium L Pimek
4 6 6 4 West Germany P Baur
West Germany A Mronz
5 7 7
4 West Germany P Baur
West Germany A Mronz
6 4 7 4 West Germany P Baur
West Germany A Mronz
7 3 6
  Australia M Fancutt
South Africa B Talbot
3 4     New Zealand S Guy
South Africa B Levine
5 6 2
  New Zealand S Guy
South Africa B Levine
6 6     New Zealand S Guy
South Africa B Levine
7 6  
  Israel M Daniel
Israel R Weidenfeld
1 3   2 United States S Davis
United States B Gilbert
6 4  
2 United States S Davis
United States B Gilbert
6 6  
[edit]