1860 United States presidential election in New Hampshire
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 County Results
Lincoln 40-50% 50-60% 60-70%
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| Elections in New Hampshire |
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The 1860 United States presidential election in New Hampshire took place on November 2, 1860, as part of the 1860 United States presidential election. Voters chose five electors of the Electoral College, who voted for president and vice president.
New Hampshire was won by Republican candidate Abraham Lincoln, who won the state by 17.61%.
Results
| 1860 United States presidential election in New Hampshire[1] | ||||||||
|---|---|---|---|---|---|---|---|---|
| Party | Candidate | Running mate | Popular vote | Electoral vote | ||||
| Count | % | Count | % | |||||
| Republican | Abraham Lincoln of Illinois | Hannibal Hamlin of Maine | 37,519 | 56.90% | 5 | 100.00% | ||
| Democratic | Stephen A. Douglas of Illinois | Herschel Vespasian Johnson of Georgia | 25,887 | 39.29% | 0 | 0.00% | ||
| Southern Democratic | John C. Breckinridge of Kentucky | Joseph Lane of Oregon | 2,125 | 3.22% | 0 | 0.00% | ||
| Constitutional Union | John Bell of Tennessee | Edward Everett of Massachusetts | 412 | 0.62% | 0 | 0.00% | ||
| Total | 65,943 | 100.00% | 5 | 100.00% | ||||
See also
References
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