1860 United States presidential election in New Hampshire
Appearance
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Results by county
Lincoln 40-49%
50-59%
60-69% | ||||||||||||||||||||||||||
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Elections in New Hampshire |
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The 1860 United States presidential election in New Hampshire took place on November 2, 1860, as part of the 1860 United States presidential election. Voters chose 5 electors of the Electoral College, who voted for president and vice president.
New Hampshire was won by Republican candidate Abraham Lincoln, who won the state by 17.61%.
Results
1860 United States presidential election in New Hampshire[1] | ||||||||
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Party | Candidate | Running mate | Popular vote | Electoral vote | ||||
Count | % | Count | % | |||||
Republican | Abraham Lincoln of Illinois | Hannibal Hamlin of Maine | 37,519 | 56.90% | 5 | 100.00% | ||
Democratic | Stephen A. Douglas of Illinois | Herschel Vespasian Johnson of Georgia | 25,887 | 39.29% | 0 | 0.00% | ||
Southern Democratic | John C. Breckinridge of Kentucky | Joseph Lane of Oregon | 2,125 | 3.22% | 0 | 0.00% | ||
Constitutional Union | John Bell of Tennessee | Edward Everett of Massachusetts | 412 | 0.62% | 0 | 0.00% | ||
Total | 65,943 | 100.00% | 5 | 100.00% |
References