1836 United States presidential election in New Jersey
 | ||||||||||||||||||||||||||
| ||||||||||||||||||||||||||
| ||||||||||||||||||||||||||
| ||||||||||||||||||||||||||
| Elections in New Jersey |
|---|
 |
The 1836 United States presidential election in New Jersey took place between November 3 and December 7, 1836, as part of the 1836 United States presidential election. Voters chose 8 representatives, or electors to the Electoral College, who voted for President and Vice President.
New Jersey voted for the Whig candidate, William Henry Harrison, over Democratic candidate Martin Van Buren. Harrison won New Jersey by a margin of 1.06%.
Results
| 1836 United States presidential election in New Jersey[1] | ||||||||
|---|---|---|---|---|---|---|---|---|
| Party | Candidate | Running mate | Popular vote | Electoral vote | ||||
| Count | % | Count | % | |||||
| Whig | William Henry Harrison of Ohio | Francis Granger of New York | 26,137 | 50.53% | 8 | 100.00% | ||
| Democratic | Martin Van Buren of New York | Richard M. Johnson of Kentucky | 25,592 | 49.47% | 0 | 0.00% | ||
| Total | 51,729 | 100.00% | 8 | 100.00% | ||||
References
- ^ "1836 Presidential General Election Results - New Jersey". U.S. Election Atlas. Retrieved 23 December 2013.
State and district results of the 1836 United States presidential election | ||
|---|---|---|
 | ||
  | This New Jersey elections-related article is a stub. You can help Wikipedia by expanding it. |