The 2019 South American U-17 Championship (Spanish: Campeonato Sudamericano Sub-17 Perú 2019, Template:Lang-pt-BR) was the 18th edition of the South American U-17 Championship, the biennial international youth football championship organised by CONMEBOL for the men's under-17 national teams of South America. It was held in Peru from 21 March to 14 April 2019.[1]
The top four teams, champions Argentina, which won their fourth title, Chile, Paraguay, and Ecuador, qualified for the 2019 FIFA U-17 World Cup in Brazil as the CONMEBOL representatives, besides Brazil who qualified automatically as hosts replacing Peru, despite failing to qualify out of the first stage as defending champions for the first time.[2]
Teams
All ten CONMEBOL member national teams entered the tournament.
Players born on or after 1 January 2002 are eligible to compete. Each team can register a squad of 23 players (three of whom must be goalkeepers).
Draw
The draw of the tournament was held on 27 February 2019, 12:00 PET (UTC−5), at the Peruvian Football Federation headquarters in Lima, Peru.[4] The ten teams were drawn into two groups of five. The host Peru and the defending champions Brazil were seeded into Group A and Group B respectively and assigned to position 1 in their group, while the remaining eight teams were placed into four "pairing pots" according to their final positions in the 2017 South American U-17 Championship (shown in brackets).[5]