1812 United States presidential election in Ohio
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| Elections in Ohio |
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The 1812 United States presidential election in Ohio took place as part of the 1812 United States presidential election. Voters chose 8 representatives, or electors to the Electoral College, who voted for President and Vice President.
Ohio re-elected incumbent Democratic-Republican President James Madison over Federalist candidate DeWitt Clinton. Madison won Ohio by a margin of 38.42%.
Results
| 1816 United States presidential election in Ohio[1] | |||||
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| Party | Candidate | Votes | Percentage | Electoral votes | |
| Democratic-Republican | James Madison | 7,420 | 69.21% | 8 | |
| Federalist | DeWitt Clinton | 3,301 | 30.79% | 0 | |
| Totals | 10,721 | 100.0% | 8 | ||
See also
References
- ^ Ohio. Secretary of State. (1909). Ohio election statistics: the general election. Springfield, Ohio: The Springfield Publishing Company, State Printers. p. 3. OCLC 5470967. Retrieved 2019-12-08.
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