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1823 Pennsylvania gubernatorial election

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1823 Pennsylvania gubernatorial election

← 1820 October 14, 1823 (1823-10-14) 1826 →
 
Nominee John Andrew Shulze Andrew Gregg
Party Democratic-Republican Federalist
Popular vote 89,928 64,211
Percentage 58.3% 41.7%

County Results
Shulze:      50-60%      60-70%      70-80%      90-100%
Gregg:      50-60%      60-70%

Governor before election

Joseph Hiester
Federalist

Elected Governor

John Andrew Shulze
Democratic-Republican

The 1823 Pennsylvania gubernatorial election occurred on October 14, 1823. Incumbent Federalist governor, Joseph Hiester, did not seek re-election. The Democratic candidate, John Andrew Shulze, defeated Federalist candidate Andrew Gregg.

Results

[edit]
Pennsylvania gubernatorial election, 1823[1][2]
Party Candidate Votes %
Democratic-Republican John Andrew Shulze 89,928 58.34
Federalist Andrew Gregg 64,211 41.66
Independent John Glosander 4 0.00
Independent N. B. Boileau 2 0.00
Independent George Bryan 1 0.00
Federalist Isaac Wayne 1 0.00
Total votes 154,147 100.00

References

[edit]
  1. ^ Dubin, Michael J. (2003). United States Gubernatorial Elections, 1776-1860: The Official Results by State and County. Jefferson, N. C.: McFarland. p. 220.
  2. ^ Lampi, Philip J. "Pennsylvania 1823 Governor". A New Nation Votes: American Election Returns 1787-1825. American Antiquarian Society. Retrieved April 30, 2024.