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1896 Swiss federal election

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The 52 electoral districts

Federal elections were held in Switzerland on 25 October 1896. The Free Democratic Party retained its majority in the National Council.[1]

Electoral system

The 147 members of the National Council were elected in 52 single- and multi-member constituencies using a three-round system. Candidates had to receive a majority in the first or second round to be elected; if it went to a third round, only a plurality was required. Voters could cast as many votes as there were seats in their constituency.[2] There was one seat for every 20,000 citizens, with seats allocated to cantons in proportion to their population.[2]

Results

Voter turnout was highest in Nidwalden at 90.3% (higher than the 89.3% in Schaffhausen where voting was compulsory) and lowest in Obwalden at 21.4%.

Party Votes % Seats +/–
Free Democratic Party 181,028 48.7 86 +12
Catholic People's Party 85,484 23.0 30 +1
Liberal Centre 54,012 14.5 21 –6
Social Democratic Party 25,304 6.8 2 +1
Democratic Group 19,946 5.4 8 –8
Others 5,750 0.0 0 0
Invalid/blank votes 26,701
Total 398,625 100 147 0
Registered voters/turnout 713,367 55.9
Source: Mackie & Rose,[3] BFS (seats)

References

  1. ^ Elections to the National Council 1848–1917: Distribution of seats by party or political orientation BFS
  2. ^ a b Dieter Nohlen & Philip Stöver (2010) Elections in Europe: A data handbook, p1886 ISBN 9783832956097
  3. ^ Thomas T Mackie & Richard Rose (1991) The International Almanac of Electoral History, Macmillan