1844 United States presidential election in Kentucky
| Elections in Kentucky |
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 Government |
The 1844 United States presidential election in Kentucky took place between November 1 and December 4, 1844, as part of the 1844 United States presidential election. Voters chose twelve representatives, or electors to the Electoral College, who voted for President and Vice President.
Kentucky voted for the Whig candidate, Henry Clay, over Democratic candidate James K. Polk. Clay won Kentucky by a margin of 8.18%.
Results
| United States presidential election in Kentucky, 1844[1] | ||||||||
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| Party | Candidate | Running mate | Popular vote | Electoral vote | ||||
| Count | % | Count | % | |||||
| Whig | Henry Clay of Kentucky | Theodore Frelinghuysen of New York | 61,249 | 54.09% | 12 | 100.00% | ||
| Democratic | James K. Polk of Tennessee | George M. Dallas of Pennsylvania | 51,988 | 45.91% | 0 | 0.00% | ||
| Total | 113,237 | 100.00% | 12 | 100.00% | ||||
References
- ^ "1844 Presidential General Election Results - Kentucky". U.S. Election Atlas. Retrieved 23 December 2013.
State and district results of the 1844 United States presidential election | ||
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