1836 United States presidential election in New Jersey

Main article: United States presidential election, 1836

United States presidential election in New Jersey, 1836

November 3 - December 7, 1836

Nominee Martin Van Buren William Henry Harrison Party Democratic Whig Home state New York Ohio Running mate Richard Mentor Johnson Francis Granger Electoral vote 8 0 Popular vote 26,137 25,592 Percentage 50.53% 49.47%

President before election Andrew Jackson Democratic Elected President Martin Van Buren Democratic

The 1836 United States presidential election in New Jersey took place between November 3 and December 7, 1836, as part of the 1836 United States presidential election. Voters chose eight representatives, or electors to the Electoral College, who voted for President and Vice President.

New Jersey voted for the Democratic candidate, Martin Van Buren, over Whig candidate William Henry Harrison. Van Buren won New Jersey by a margin of 1.06%.

Results

United States presidential election in New Jersey, 1836
Party		Candidate	Running mate	Popular vote		Electoral vote
				Count	%	Count	%
	Democratic	Martin Van Buren of New York	Richard M. Johnson of Kentucky	26,137	50.53%	8	100.00%
	Whig	William Henry Harrison of Ohio	Francis Granger of New York	25,592	49.47%	0	0.00%
Total				51,729	100.00%	8	100.00%