1856 United States presidential election in New Jersey
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| Elections in New Jersey |
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The 1856 United States presidential election in New Jersey took place on November 4, 1856, as part of the 1856 United States presidential election. Voters chose 35 representatives, or electors to the Electoral College, who voted for President and Vice President.
New Jersey voted for the Democratic candidate, James Buchanan, over Republican candidate, John C. Frémont, and the Know Nothing candidate, Millard Fillmore. Buchanan won the state by a margin of 13.43%.
Results
| United States presidential election in New Jersey, 1856[1] | ||||||||
|---|---|---|---|---|---|---|---|---|
| Party | Candidate | Running mate | Popular vote | Electoral vote | ||||
| Count | % | Count | % | |||||
| Democratic | James Buchanan of Pennsylvania | John C. Breckinridge of Kentucky | 46,943 | 47.23% | 7 | 100.00% | ||
| Republican | John C. Frémont of California | William L. Dayton of New Jersey | 28,338 | 28.51% | 0 | 0.00% | ||
| Know Nothing | Millard Fillmore of New York | Andrew Jackson Donelson of Tennessee | 24,115 | 24.26% | 0 | 0.00% | ||
| Total | 99,396 | 100.00% | 7 | 100.00% | ||||
References
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