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1824 United States presidential election in North Carolina

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United States presidential election in North Carolina, 1824

← 1820 October 26 – December 2, 1824 1828 →
 
Nominee Andrew Jackson William H. Crawford
Party Democratic-Republican Democratic-Republican
Home state Tennessee Georgia
Running mate John C. Calhoun Nathaniel Macon
Electoral vote 15 0
Popular vote 20,231 15,622
Percentage 56.03% 43.26%

President before election

James Monroe
Democratic-Republican

Elected President

John Quincy Adams
Democratic-Republican

The 1824 United States presidential election in North Carolina took place between October 26 and December 2, 1824, as part of the 1824 United States presidential election. Voters chose 15 representatives, or electors to the Electoral College, who voted for President and Vice President.

During this election, the Democratic-Republican Party was the only major national party, and four different candidates from this party sought the Presidency. North Carolina voted for Andrew Jackson over William H. Crawford, Henry Clay, and John Quincy Adams. Jackson won North Carolina by a margin of 12.77%.

Results

United States presidential election in North Carolina, 1824[1]
Party Candidate Votes Percentage Electoral votes
Democratic-Republican Andrew Jackson 20,231 56.03% 15
Democratic-Republican William H. Crawford 15,622 43.26% 0
N/A Others 256 0.71% 0
Totals 36,109 100.0% 15

References

  1. ^ "1824 Presidential General Election Results - North Carolina". U.S. Election Atlas. Retrieved 27 February 2013.